1 solutions
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0
C :
#include<stdio.h> int main() { int t,n,m,c1,c2,c5,k; scanf("%d",&t); while(t--) { scanf("%d%d",&n,&m); k=0; for(c5=0;5*c5<=m;c5++) for(c2=0;2*c2+5*c5<=m;c2++) { c1=m-5*c5-2*c2; if(c1+c2+c5==n) k++; } printf("%d\n",k); } return 0; }
C++ :
#include<stdio.h> int main() { int t,n,m,c1,c2,c5,k; scanf("%d",&t); while(t--) { scanf("%d%d",&n,&m); k=0; for(c5=0;5*c5<=m;c5++) for(c2=0;2*c2+5*c5<=m;c2++) { c1=m-5*c5-2*c2; if(c1+c2+c5==n) k++; } printf("%d\n",k); } return 0; }
- 1
Information
- ID
- 10035
- Time
- 1000ms
- Memory
- 32MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By