1 solutions
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0
C :
#include <stdio.h> int main() { int n,counter,a[100]; while(scanf("%d",&n)==1) { counter=0; for(int i=0;i<n;i++) { scanf("%d",&a[i]); if(a[i]==90) counter++; } printf("%d\n",counter); break; } return 0; }
C++ :
#include<iostream> using namespace std; int main() { int n,a,count=0; cin>>n; while(n--) { cin>>a; if(a==90) count++; } cout<<count<<endl; return 0; }
- 1
Information
- ID
- 10037
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By