1 solutions
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0
C++ :
#include <bits/stdc++.h> using namespace std; int main() { int m,n,a[1005],b[1005],flag,cnt=0; cin>>m>>n; for(int i=1;i<=n;i++)cin>>a[i]; int L=0,R=1; memset(b,-1,sizeof(b)); for(int i=1;i<=n;i++) { flag=1; for(int j=L;j<=R;j++) { if(b[j]==a[i]) { flag=0; break; } } if(flag) { cnt++; if(R-L>=m)L++; b[R++]=a[i]; } } cout<<cnt<<endl; return 0; }
- 1
Information
- ID
- 10046
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By