1 solutions
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0
C :
#include<stdio.h> int n,d,i,s,sum,k; int main() { while(~scanf("%d",&n)&&n) { d=0;sum=0; for(i=1;i<=n;i++) { scanf("%d",&s); k=s-d; if(k>0) sum+=6*k; else sum+=-4*k; d=s; } sum+=n*5; printf("%d\n",sum); } return 0; }
C++ :
#include<stdio.h> int a[105]; int main() { //freopen("1234.txt","r",stdin); //freopen("out.txt","w",stdout); int n; while(scanf("%d",&n)!=EOF) { if(n==0) break; int sum=0; for(int i=1;i<=n;i++) scanf("%d",&a[i]); for(int i=1;i<=n;i++) { if(a[i]-a[i-1]>0) sum+=(a[i]-a[i-1])*6; else sum+=(a[i-1]-a[i])*4; } sum+=5*n; printf("%d\n",sum); } return 0; }
- 1
Information
- ID
- 10048
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By