1 solutions
-
0
C :
#include<stdio.h> int main() { int a,b,c,s; scanf("%d%d%d",&a,&b,&c); s=a*0.2+b*0.3+c*0.5; printf("%d",s); return 0; }
C++ :
#include<bits/stdc++.h> using namespace std; int main() { int a,b,c; scanf("%d%d%d",&a,&b,&c); int x=a*0.2+b*0.3+c*0.5;//第一次强制转化 printf("%d",x); }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); double a = sc.nextInt(); double b = sc.nextInt(); double c = sc.nextInt(); int d = 0; d =(int)( a * 0.2 + b * 0.3 + c * 0.5); System.out.println(d); sc.close(); } }
Python :
s=input().split() x=int(s[0]) y=int(s[1]) z=int(s[2]) a=x*0.2+y*0.3+z*0.5 print(int(a))
- 1
Information
- ID
- 10087
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By