1 solutions
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0
C++ :
#include <bits/stdc++.h> using namespace std; int a[210],n,m,x; int main(){ cin>>n>>m; for(int i = 1;i <= m;i++){ cin>>x; a[x]++; } int ma = 1; for(int i = 1;i <= n;i++){ if(a[i] > a[ma]) ma = i; } cout<<ma; return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int num1 = scanner.nextInt(); int num2 = scanner.nextInt(); int[] a = new int[num2]; int[] b = new int[1000]; int[] count = new int[10000]; double avg; int x = 0; long s = 0; for (int i = 0; i < num2; i++) { a[i] = scanner.nextInt(); } for(int i = 0;i < num2;i++){ count[a[i]]++; } int max = MAX(count); for (int i = 0; i < 10000; i++) { if(count[i] == max){ System.out.println(i); break; } } } public static boolean judge(int i,int j){ int a,s = 0; while(i != 0){ a = i % 10; s = s + a; i /= 10; } if(s == j)return true; else return false; } public static void paiXux(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } }public static void paiXu(int[] a,int length){ int temp; for(int i = 0;i < length - 1;i++){ for(int k = 0;k < length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXud(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] < a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } public static int sum(int a){ int x,s = 0; while(a != 0){ x = a % 10; s = s + x; a /= 10; } return s; } public static boolean isPrime(int a){ if(a <= 1)return false; else for(int i = 2;i <= Math.sqrt(a);i++){ if(a % i == 0)return false; }return true; } public static int qiuYu(int i){ int a; a = i % 10; return a; } }
Python :
sr=input().split() m=int(sr[0]) n=int(sr[1]) a=input().split() a=list(map(int,a)) a=sorted(a) b=[] for i in range(n): if (a[i] not in b): b.append(a[i]) da=a.count(b[0]) k=0 for i in range(len(b)): if(a.count(b[i])>da): da=a.count(b[i]) k=i print(b[k])
- 1
Information
- ID
- 10127
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By