1 solutions

  • 0
    @ 2025-3-3 16:28:34

    C :

    #include<stdio.h>
    int main()
    {
    	int a,b,c;
    	scanf("%d",&a);
    	printf("%d\n%d\n%.1f",a*3,a*3-8,(a*7-8)*1.0/3);
    	return 0;
    }
    

    C++ :

    #include<iostream>
    #include <iomanip>
    using namespace std;
    int main(){
    	int x;
    	cin>>x;
    	cout<<x*3<<endl;
    	cout<<x*3-8<<endl;
    	cout<<fixed<<setprecision(1)<<(x*3+x*3-8+x)/3.0<<endl;
    } 
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    	 
        /**
         * @param args
         */
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		int a = sc.nextInt();
    		int b = a * 3;
    		int c = b - 8;
    		double get = (double)(a+b+c)/3;
    		System.out.println(b);
    		System.out.println(c);
    		System.out.println( String.format("%.1f", get));
    		
    	}
    	public static void printArr(int [] a){
    		for (int i = 0 ;i<= a.length - 1 ;i++) {
    			System.out.print( a[i] + " ");
    		}
    	}
    }
    

    Python :

    x = int(input())
    a = x * 3
    print(a)
    b = a - 8
    print(b)
    su = x + a + b
    print("%.1f" % (su / 3))
    
    
    • 1

    Information

    ID
    10173
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    (None)
    Tags
    # Submissions
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