1 solutions
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0
C :
#include<stdio.h> int main() { int a,b,c; scanf("%d",&a); printf("%d\n%d\n%.1f",a*3,a*3-8,(a*7-8)*1.0/3); return 0; }
C++ :
#include<iostream> #include <iomanip> using namespace std; int main(){ int x; cin>>x; cout<<x*3<<endl; cout<<x*3-8<<endl; cout<<fixed<<setprecision(1)<<(x*3+x*3-8+x)/3.0<<endl; }
Java :
import java.util.Scanner; public class Main { /** * @param args */ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int a = sc.nextInt(); int b = a * 3; int c = b - 8; double get = (double)(a+b+c)/3; System.out.println(b); System.out.println(c); System.out.println( String.format("%.1f", get)); } public static void printArr(int [] a){ for (int i = 0 ;i<= a.length - 1 ;i++) { System.out.print( a[i] + " "); } } }
Python :
x = int(input()) a = x * 3 print(a) b = a - 8 print(b) su = x + a + b print("%.1f" % (su / 3))
- 1
Information
- ID
- 10173
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By