1 solutions
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0
C :
#include<stdio.h> int main() { int a; scanf("%d",&a); printf("%d\n%.1f",a/100+a%100,(a/100)*1.0/(a%100)); return 0; }
C++ :
#include <iostream> #include <iomanip> using namespace std; int main(){ int n,g,s,b,q; cin>>n; q = n / 1000; b = n / 100 % 10; s = n / 10 % 10; g = n % 10; cout<<q*10+b+s*10+g<<endl; cout<<fixed<<setprecision(1)<<(q*10+b)*1.0/(s*10+g); }
Java :
import java.util.Scanner; public class Main { /** * @param args */ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int a = sc.nextInt(); int g = a%10; int s = a/10 %10; int b = a/100 %10; int q = a/1000; int x = b + q*10; int y = g + s*10; System.out.println(x+y); System.out.println(String.format("%.1f", (double)x/y)); } public static void printArr(int [] a){ for (int i = 0 ;i<= a.length - 1 ;i++) { System.out.print( a[i] + " "); } } }
Python :
n = int(input()) q = n // 1000 % 10 b = n // 100 % 10 s = n // 10 % 10 g = n // 1 % 10 x = q * 10 + b y = s * 10 + g print(x + y) print("%.1f" % (x / y))
- 1
Information
- ID
- 10180
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By