1 solutions
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0
C :
#include<stdio.h> int main() { int a,b,c; scanf("%d",&a); printf("%d\n",a); printf("%d\n",a+8); printf("%d\n",a+6); printf("%.1f",(3*a+14)*1.0/3); return 0; }
C++ :
#include<bits/stdc++.h> using namespace std; int main() { int n; cin>>n; cout<<n<<endl; cout<<n+8<<endl; cout<<n+6<<endl; cout<<fixed<<setprecision(1)<<(n+n+8+n+6)/3.0<<endl; return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int y = n + 8; int b = y - 2; double p =(double) (n + y + b) /3; System.out.println(n); System.out.println(y); System.out.println(b); System.out.println(String.format("%.1f", p)); } }
Python :
a=int(input()) b=a+8 c=b-2 print(a) print(b) print(c) print("%.1lf"%((a+b+c)/3))
- 1
Information
- ID
- 10183
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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