1 solutions

  • 0
    @ 2025-3-3 16:28:34

    C :

    #include<stdio.h>
    
    void main(){
    	int x;
    	double p;
    	scanf("%d",&x);
    	
    	p=0.9*x;
    	
    	printf("%.1f",p);
    }
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n;
    	cin>>n;
    	cout<<fixed<<setprecision(1)<<(n+n*0.8+n*0.9) / 3;
    }
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		double x = sc.nextDouble();
    		double a = x * 0.8;
    		double b = x * 0.9;
    		double p =(double) (x + a + b) / 3;
    		System.out.println(String.format("%.1f", p));
    	}
    }
    

    Python :

    a=int(input())
    b=a*0.8
    c=a*0.9
    print("%.1lf"%((a+b+c)/3))
    
    
    • 1

    Information

    ID
    10184
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    (None)
    Tags
    # Submissions
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