1 solutions

  • 0
    @ 2025-3-3 16:28:34

    C :

    #include<stdio.h>
    int main()
    {
        int m,n,t,s;
        scanf("%d%d%d",&m,&n,&t);
       
        s=t+m+n;
        if(s>=270)
            printf("beijing");
        else
            printf("nanjing");
        return 0;
    }
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
        int x,y,z;
        cin>>x>>y>>z;
        double r = (x + y + z) / 3.0;
        if(r >= 90){
        	cout<<"beijing";
    	}else{
    		cout<<"nanjing";
    	}
    }
     
    
    

    Java :

    import java.util.Scanner;
    public class Main
    {
    	public static void main(String[] Args)
    	{
    		Scanner sc = new Scanner(System.in);
    		int a = sc.nextInt();
    		int b = sc.nextInt();
    		int c = sc.nextInt();
    		int d = (a + b +c)/3;
    		if(d>=90)
    			System.out.println("beijing");
    		else
    			System.out.println("nanjing");
    	}
    }
    

    Python :

    n = input().split()
    x = int(n[0])
    y = int(n[1])
    z = int(n[2])
    su = x + y + z
    if su / 3 >= 90:
        print('beijing')
    else:
        print('nanjing')
    
    
    • 1

    Information

    ID
    10195
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    (None)
    Tags
    # Submissions
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