1 solutions
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0
C :
#include<stdio.h> int main() { int m,n,t,s; scanf("%d%d%d",&m,&n,&t); s=t+m+n; if(s>=270) printf("beijing"); else printf("nanjing"); return 0; }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int x,y,z; cin>>x>>y>>z; double r = (x + y + z) / 3.0; if(r >= 90){ cout<<"beijing"; }else{ cout<<"nanjing"; } }
Java :
import java.util.Scanner; public class Main { public static void main(String[] Args) { Scanner sc = new Scanner(System.in); int a = sc.nextInt(); int b = sc.nextInt(); int c = sc.nextInt(); int d = (a + b +c)/3; if(d>=90) System.out.println("beijing"); else System.out.println("nanjing"); } }
Python :
n = input().split() x = int(n[0]) y = int(n[1]) z = int(n[2]) su = x + y + z if su / 3 >= 90: print('beijing') else: print('nanjing')
- 1
Information
- ID
- 10195
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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