1 条题解

  • 0
    @ 2025-3-3 16:28:35

    C :

    #include<string.h>
    #include<stdio.h>
    int main()
    {
        int m,a,c,b;
        scanf("%d",&m);
        a=m/100;
        b=m/10%10;
        c=m%10;
        if(a>b&&b>c)
            printf("%d",a-c);
        if(a>c&&c>b)
            printf("%d",a-b);
        if(c>b&&b>a)
            printf("%d",c-a);
        if(c>a&&a>b)
            printf("%d",c-b);
        if(b>a&&a>c)
            printf("%d",b-c);
        if(b>c&&c>a)
            printf("%d",b-a);
        return 0;
    }
    
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    int main(){
    	int n;
    	cin>>n;
    	int b = n / 100;
    	int s = n / 10 % 10;
    	int g = n % 10;
    	
    	int ma = b;
    	int mi = b;
    	if(s > ma) ma = s;
    	if(s < mi) mi = s;
    	if(g > ma) ma = g;
    	if(g < mi) mi = g;
    	
    	cout<<ma - mi;
    }
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Scanner sc = new Scanner(System.in);
    		int n = sc.nextInt();
    		int a = n % 10;
    		int b = n / 10 % 10;
    		int c = n / 100;
    		int t;
    		if(a > b){
    			t = a;
    			a = b;
    			b = t;
    		}if(b > c){
    			t = b;
    			b = c;
    			c = t;
    		}if(a > b){
    			t = a;
    			a = b;
    			b = t;
    		}
    		int s = c - a;
    		System.out.println(s);
    		sc.close();
    	}
    
    }
    

    Python :

    n = int(input())
    b = n // 100
    s = n // 10 % 10
    g = n // 1 % 10
    if b > s and b > g and s > g:
        print(b - g)
    if b > s and b > g and s < g:
        print(b - s)
    if s > b and s > g and b > g:
        print(s - g)
    if s > b and s > g and b < g:
        print(s - b)
    if g > s and g > b and s > b:
        print(g - b)
    if g > s and g > b and s < b:
        print(g - s)
    
    
    • 1

    信息

    ID
    10209
    时间
    1000ms
    内存
    16MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者