1 solutions

  • 0
    @ 2025-3-3 16:28:35

    C :

    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    #include<ctype.h>
    #include<math.h>
    int n,k,mx;
    int main(){
    	int i,t;
    	scanf("%d",&n);
    	scanf("%d",&t);
    	k = 1,mx = t;
    	for(i=2;i<=n;i++){
    		scanf("%d",&t);
    		if(t>mx){
    			mx = t;
    			k = i;
    		}
    	}
    	printf("%d %d",mx,k);
    	return 0;
    }
    
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n;
    	int x,z;
    	cin>>n;
    	int a[1000],i;
    	for(i=0;i<n;i++){
    		cin>>a[i];	
    	}
    	x=a[0];
    	for(i=0;i<n-1;i++){
    		if(a[i+1]>x){
    			x=a[i+1];
    			z=i+2;
    		}
    	}
    	cout<<x<<" "<<z;
    }
    
    • 1

    Information

    ID
    10217
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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