1 solutions
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0
C :
#include<stdio.h> #include<stdlib.h> #include<string.h> #include<ctype.h> #include<math.h> int n,k,mx; int main(){ int i,t; scanf("%d",&n); scanf("%d",&t); k = 1,mx = t; for(i=2;i<=n;i++){ scanf("%d",&t); if(t>mx){ mx = t; k = i; } } printf("%d %d",mx,k); return 0; }
C++ :
#include<bits/stdc++.h> using namespace std; int main() { int n; int x,z; cin>>n; int a[1000],i; for(i=0;i<n;i++){ cin>>a[i]; } x=a[0]; for(i=0;i<n-1;i++){ if(a[i+1]>x){ x=a[i+1]; z=i+2; } } cout<<x<<" "<<z; }
- 1
Information
- ID
- 10217
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By