1 solutions

  • 0
    @ 2025-3-3 16:28:35

    C :

    #include<stdio.h>
    
    void main(){
    	int n,i,g;
    	scanf("%d",&n);
    	
    	i=1;
    	while(i<=n){
    		g=i%10;
    		if(g==1||g==3||g==5||g==7){
    			printf("%d\n",i);
    		}
    		i++;
    	}
    } 
    
    
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main() {
    	int i,n,g;
    	cin>>n;
    	i = 1;
    	while(i <= n){
    		g = i % 10;
    		if(g == 1 || g == 3 || g == 5 || g == 7){
    			cout<<i<<endl;
    		}
    		i = i + 1;
    	}
    }
    
    

    Java :

    import java.util.Scanner;
    
    public class Main {
    
    	public static void main(String[] args) {
    		Scanner sc = new Scanner(System.in);
    		int n = sc.nextInt();
    		for(int i=1;i<=n;i++) {
    			int g = i % 10;
    			if(g==1 || g==3 || g==5 || g==7) {
    				System.out.println(i);
    			}
    		}
    
    	}
    
    }
    

    Python :

    #接收输入整数
    n = int(input())
    #从1~n的for循环
    for i in range(1, n + 1):
        #计算个位数值
        gw = i % 10
        #如果个位数=1 或=3 或=5 或=7时,打印此时的i值
        if gw == 1 or gw == 3 or gw == 5 or gw == 7:
            print(i)
    
    
    • 1

    Information

    ID
    10226
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    (None)
    Tags
    # Submissions
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