1 solutions
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0
C :
#include<stdio.h> void main(){ int n; double p; scanf("%d",&n); if(n<10&&n>0){ p=n*1.5; }else if(n>=10){ p=n*1.2; } printf("%.1f",p); }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; double r; if(n < 10){ r = n * 1.5; }else{ r = n * 1.2; } cout<<fixed<<setprecision(1)<<r; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); int n = sc.nextInt(); double s; if(n < 10){ s =(double)(n * 1.5); System.out.println(String.format("%.1f", s)); }else if(n >= 10){ s =(double)(n * 1.2); System.out.println(String.format("%.1f", s)); } } }
Python :
n = int(input()) if n < 10: print('%.1f' % (n * 1.5)) if n >= 10: print('%.1f' % (n * 1.2))
- 1
Information
- ID
- 10229
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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