1 solutions
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0
C :
#include<stdio.h> void main(){ int n,a,b,c; int p; scanf("%d%d%d%d",&n,&a,&b,&c); if(n>=(a+b+c)){ p=n-a-b-c; printf("%d",p); printf(" "); printf("%s","YES"); }else{ p=a+b+c-n; printf("%d",p); printf(" "); printf("%s","NO"); } }
C++ :
#include<bits/stdc++.h> using namespace std; int main(){ int a,b,c,n,z,q; cin>>n>>a>>b>>c; q=a+b+c; z=n-q; if(n>=q)cout<<z<<" "<<"YES"<<endl; else cout<<abs(z)<<" "<<"NO"<<endl; return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int a = sc.nextInt(); int b = sc.nextInt(); int c = sc.nextInt(); int s = a + b + c; int d; if(n >= s){ d = n - s; System.out.println(d + " " + "YES"); }else if(n < s){ d = s - n; System.out.println(d + " " + "NO"); } } }
Python :
s = input().split() n = int(s[0]) a = int(s[1]) b = int(s[2]) c = int(s[3]) su = a + b + c if n >= su: print(str(n - su) + ' ' + 'YES') else: print(str(su - n) + ' ' + 'NO')
- 1
Information
- ID
- 10230
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By