1 solutions

  • 0
    @ 2025-3-3 16:29:41

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    
    int main(){
         int a[100010];
         int f[100010] = {0};//标记某个数是否出现过的数组(类似桶排序的那个概念)
         int n,m,x,i,j,t;
         cin>>n;
         cin>>m;
    	 for(i = 0;i < m;i++){
    		cin>>a[i];
    	 }
    	
    	 //输出
    	 for(i = m - 1;i >= 0;i--){
    		//如果a[i]在前面已出现则不输出
    		if(f[a[i]] == 0){
    			cout<<a[i]<<" ";
    			f[a[i]] = 1;
    		}
    	 } 
    	
    	 //看一下1~n中哪些数没有放入数组的,放进来
    	 for(i = 1;i <= n;i++){
    		 if(f[i] == 0){
    		   cout<<i<<" "; 
    		 }
    	 } 
    }
    
    
    
    • 1

    Information

    ID
    10293
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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