1 solutions
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0
C :
#include <stdio.h> int main() { int num; int sum=0;//因子之和 scanf("%d",&num); int i; for(i=1; i<=num/2; i++) { if(num%i==0) sum+=i; } if(sum==num) printf("yes\n"); else printf("no\n"); return 0; }
C++ :
#include<iostream> #include<cmath> using namespace std; long long a,gs=0; int main() { cin>>a; for(int i=1; i<a; i++) { if(a%i==0) gs+=i; } if(gs==a) cout<<"yes"; else cout<<"no"; return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int a = scanner.nextInt(); // int b = scanner.nextInt(); int s = 0; for(int i = 1;i < a;i++){ if(a % i == 0)s = s + i; } if(s == a) System.out.println("yes"); else System.out.println("no"); }public static void paiXu(int[] a,int length){ int temp; for(int i = 0;i < length - 1;i++){ for(int k = 0;k < length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXud(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] < a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static void paiXux(int[] a){ int temp; for(int i = 0;i < a.length - 1;i++){ for(int k = 0;k < a.length - i - 1;k++){ if(a[k] > a[k + 1]){ temp = a[k]; a[k] = a[k + 1]; a[k + 1] = temp; } } } } public static int MAX(int[] a){ int max = a[0]; for (int i = 0; i < a.length; i++) { if(max < a[i]){ max = a[i]; } } return max; } public static int MIN(int[] a){ int min = a[0]; for (int i = 0; i < a.length; i++) { if(min > a[i]){ min = a[i]; } } return min; } public static int sum(int a){ int x,s = 0; while(a != 0){ x = a % 10; s = s + x; a /= 10; } return s; } public static boolean isPrime(int a){ if(a <= 1)return false; else for(int i = 2;i <= Math.sqrt(a);i++){ if(a % i == 0)return false; }return true; } public static long qiuYu(long i){ long a; a = i % 10; return a; } public static int daoXu(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s * 10 + x; x /= 10; } return s; } public static int jiaWei(int x){ int s = 0,m; while(x != 0){ m = x % 10; s = s + m; x /= 10; } return s; } }
Python :
n=int(input()) s=0 for i in range(1,n//2+1): if(n%i==0): s=s+i if(s==n): print("yes") else: print("no")
- 1
Information
- ID
- 10355
- Time
- 1000ms
- Memory
- 512MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By