1 solutions
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0
C :
#include<stdio.h> int main() { int c; scanf("%d",&c); printf("%.2f",(c*1.0/4)*(c*1.0/4)); return 0; }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; cout<<fixed<<setprecision(2)<<n/4.0*n/4.0<<endl; }
Python :
a=int(input()) b=a/4 print("%.2lf"%(b*b))
- 1
Information
- ID
- 10416
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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