1 solutions
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0
C :
#include<stdio.h> void main(){ int i,n; double x; scanf("%lf%d",&x,&n); for(i=1;i<=n;i++){ x=x+x*0.001; } printf("%.4f",x); }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int x,n; cin>>x>>n; double r = x; for(int i = 1;i <= n;i++){ r = r * 1.001; } cout<<fixed<<setprecision(4)<<r<<endl; }
Python :
n = input().split() a = int(n[0]) b = int(n[1]) su = 0 for i in range(1, b + 1): su = a * (1 + 0.001) ** i print('%.4f' % su)
- 1
Information
- ID
- 10442
- Time
- 1000ms
- Memory
- 32MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By