1 solutions

  • 0
    @ 2025-3-3 16:32:52

    C :

    #include<stdio.h>
    
    void main(){
        int i,n;
        double x;
        scanf("%lf%d",&x,&n);
    
        for(i=1;i<=n;i++){
            x=x+x*0.001;
        }
        printf("%.4f",x);
    }
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
    	int x,n;
    	cin>>x>>n;
    	double r = x;
    	for(int i = 1;i <= n;i++){
    		r = r * 1.001;
    	}
    	cout<<fixed<<setprecision(4)<<r<<endl;
    }
    

    Python :

    n = input().split()
    a = int(n[0])
    b = int(n[1])
    su = 0
    for i in range(1, b + 1):
        su = a * (1 + 0.001) ** i
    print('%.4f' % su)
    
    • 1

    Information

    ID
    10442
    Time
    1000ms
    Memory
    32MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By