1 solutions
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0
C :
#include <stdio.h> void main() { int a ,b,c,d,e,f,g,h,min; scanf("%d %d %d %d",&a, &b ,&c ,&d); g=a*60+b;h=c*60+d; min=h-g; e=min/60;f=min-e*60; printf("%d %d",e,f); }
C++ :
#include <iostream> using namespace std; int main(){ int a,b,c,d; cin>>a>>b>>c>>d; int t1 = a * 60 + b; int t2 = c * 60 + d; int t = t2 - t1; cout<<t / 60<<" "<<t % 60<<endl; }
Python :
a,b,c,d=map(int,input().split()) if d>=b: f=d-b e=c-a elif d<b: f=d+60-b e=c-1-a print(e,f)
- 1
Information
- ID
- 10458
- Time
- 1000ms
- Memory
- 32MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By