1 条题解
- 
  0
C :
#include<stdio.h> int main(){ int i,j,n; scanf("%d",&n); for(i=1;i<=n;i++){ for(j=1;j<=n-i;j++){ printf("*"); } for(j=1;j<=2*i-1;j++){ printf("@"); } for(j=1;j<=n-i;j++){ printf("*"); } printf("\n"); } return 0; }C++ :
#include <iostream> using namespace std; int main(){ int i,j,n; cin>>n; for(i = 1;i <= n;i++){ for(j = 1;j <= n - i;j++) cout<<"*"; for(j = 1;j <= 2 * i - 1;j++) cout<<"@"; for(j = 1;j <= n - i;j++) cout<<"*"; cout<<endl; } }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc= new Scanner(System.in); int a = sc.nextInt(); sc.close(); for(int i=1;i<=a;i++) { for(int j=1;j<=a-i;j++) { System.out.print("*"); } for(int k=1;k<=i*2-1;k++) { System.out.print("@"); } for(int j=1;j<=a-i;j++) { System.out.print("*"); } System.out.println(); } } }Python :
n = int(input()) for i in range(1, n + 1): for j in range(1, n - i + 1): print("*", end='') for j in range(1, 2 * i): print('@', end='') for j in range(1, n - i + 1): print("*", end='') print() 
- 1
 
信息
- ID
 - 10490
 - 时间
 - 1000ms
 - 内存
 - 128MiB
 - 难度
 - (无)
 - 标签
 - 递交数
 - 0
 - 已通过
 - 0
 - 上传者