1 solutions
-
0
C :
#include <stdio.h> int main() { int mark[4]; int i,sum=0; for (i=0;i<4;i++) { scanf ("%d",&mark[i]); if (mark[i]>=90) { sum+=1; } } switch (sum) { case 4:printf("%s","A");break; case 3: case 2: printf("%s","B");break; case 1:printf("%s","C");break; case 0:printf("%s","D");break; } return 0; }
C++ :
#include<bits/stdc++.h> using namespace std; int main() { int a,b,c,d,s=0; cin>>a>>b>>c>>d; if(a>=90) s=s+1; if(b>=90) s=s+1; if(c>=90) s=s+1; if(d>=90) s=s+1; if(s==4) cout<<"A"; else if(s>=2) cout<<"B"; else if(s==1) cout<<"C"; else cout<<"D"; return 0; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); int a = sc.nextInt(); int b = sc.nextInt(); int c = sc.nextInt(); int d = sc.nextInt(); if(a>=90 && b>=90 && c>=90 && d>=90){ System.out.println("A"); }else if(a<90 && b<90 && c<90 && d<90){ System.out.println("D"); }else if((a>=90 && b<90 && c<90 && d<90) || (a<90 && b>=90 && c<90 && d<90) || (a<90 && b<90 && c>=90 && d<90) || (a<90 && b<90 && c<90 && d>=90)){ System.out.println("C"); }else if((a<90 && b>=90 && c>=90 && d>=90) || (a>=90 && b<90 && c>=90 && d>=90) || (a>=90 && b>=90 && c<90 && d>=90) || (a>=90 && b>=90 && c>=90 && d<90) || (a<90 && b<90 && c>=90 && d>=90) || (a<90 && b>=90 && c<90 && d>=90) || (a<90 && b>=90 && c>=90 && d<90) || (a>=90 && b<90 && c<90 && d>=90) || (a>=90 && b<90 && c>=90 && d<90) || (a>=90 && b>=90 && c<90 && d<90)){ System.out.println("B"); } } }
- 1
Information
- ID
- 10509
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By