1 solutions
-
0
C :
#include<stdio.h> int main() { int x,a,b,c,d,max=0; scanf("%d",&x); a=x/1000; b=x/100%10; c=x/10%10; d=x%10; if(a>max) max=a; if(b>max) max=b; if(c>max) max=c; if(d>max) max=d; printf("%d",max); return 0; }
C++ :
#include <bits/stdc++.h> using namespace std; int main() { int a[4],n; cin>>n; a[0] = n / 1000; a[1] = n / 100 % 10; a[2] = n / 10 % 10; a[3] = n % 10; sort(a,a+4); cout<<a[3]; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args){ Scanner sc = new Scanner(System.in); int x = sc.nextInt(); int a = x/1000; int b = x/100%10; int c = x/10%10; int d = x%10; int max =a; if(max<b) { max = b; } if(max<c) { max = c; } if(max<d) { max = d; } System.out.println(max); } }
Python :
n = int(input()) q = n // 1000 % 10 b = n // 100 % 10 s = n // 10 % 10 g = n // 1 % 10 mx = max(g, s, b, q) print(mx)
- 1
Information
- ID
- 10546
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By