1 solutions
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0
C++ :
#include <bits/stdc++.h> using namespace std; int i,n,c = 0; int main() { cin>>n; for(i = 1;i <= n;i++){ if(i*i%10==i||i*i%100==i||i*i%1000==i||i*i%10000==i||i*i%100000==i||i*i%1000000==i){ c++; //cout<<i<<endl; } } cout<<c; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int s = 0 ; for(int i = 1 ; i <= n ; i++) { if((i*i)%10 == i || (i*i)%100 == i || (i*i)%1000 == i || (i*i)%10000 == i ||(i*i)%100000 == i) { s++; } } System.out.println(s); } }
Python :
# 接收输入:思路是转换为字符串来处理 n = int(input()) c = 0 for i in range(1, n + 1): # 平方的结果转成字符串 a = str(i * i) # 把i转化成字符串 b = str(i) # 得到i字符串的位数 t = len(b) if a[t*(-1):] == b: c += 1 print(c)
- 1
Information
- ID
- 10556
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By