1 solutions

  • 0
    @ 2025-3-3 16:33:15

    C :

    #include<stdio.h>
    int main()
    {
        int x;
        scanf("%d",&x);
      
        if(x==1)
            printf("%.1lf",5.0);
        if(x>=2&&x<=5)
            printf("%.1lf",4.5*x);
        if(x>=6&&x<=10)
            printf("%.1lf",4.0*x);
        if(x>10)
            printf("%.1lf",3.5*x);
            return 0;
    }
    
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
        int n;
        double r;
        cin>>n;
        
        if(n == 1){
        	r = 5;
    	}else if(n >= 2 && n <= 5){
    		r = n * 4.5;
    	}else if(n >= 6 && n <= 10){
    		r = n * 4;
    	}else if(n > 10){
    		r = n * 3.5;
    	}
    	
    	cout<<fixed<<setprecision(1)<<r;
    }
    
    

    Java :

    import java.util.Scanner;
    public class Main
    {   
    	public static void main(String[] args){
            Scanner sc = new Scanner(System.in);
            int x = sc.nextInt();
            double a = x*5.0;
            double b = x*4.5;
            double c = x*4.0;
            double d = x*3.5;
            if(x>10) {
            	System.out.println(d);
            }else if(x>=6) {
            	System.out.println(c);
            }else if(x>=2) {
            	System.out.println(b);
            }else {
            	System.out.println(a);
            }
           
        
        }
    }
    

    Python :

    n = int(input())
    if n == 1:
        p = 5
    elif 2 <= n <= 5:
        p = 4.5
    elif 6 <= n <= 10:
        p = 4
    else:
        p=3.5
    print("%.1f" % (n*p))
    
    
    • 1

    Information

    ID
    10560
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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