1 solutions

  • 0
    @ 2025-3-3 16:33:27

    C :

    #include<stdio.h>
    int a[10][10];
    main()
    {
    	int i,j,m,n,x;
    	scanf("%d%d",&m,&n);
    	for(i=0;i<m;i++)
    	{
    		for(j=0;j<n;j++)
    		{
    			scanf("%d",&x);
    			a[i][j]=x;
    		}
    	}
    	int t=0,g=0;
    	for(i=0;i<m;i++)
    	{
    		for(j=0;j<n;j++)
    		{
    			if(a[i][j]==1&&a[i][j]==0)
    			{
    				t++;
    			}
    			if(a[i][j]!=1&&a[i][j]!=0)
    			{
    			    g=1;
    			}
    		}
    	}
    	if(g==1)
    	printf("No");
    	else
    	printf("Yes");
    }
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main() {
    	int a[20][20],m,n;
    	bool f=true;
    	cin>>n>>m;
    	for(int i=0;i<n;i++){
    		for(int j=0;j<m;j++){
    			cin>>a[i][j];
    			if(a[i][j]!=0&&a[i][j]!=1){
    				f=false;
    			}
    		}
    	}
    	if(f==true){
    		cout<<"Yes"<<endl;
    	}else{
    		cout<<"No"<<endl;
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    10580
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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