1 solutions

  • 0
    @ 2025-3-3 16:33:28

    C :

    #include<stdio.h>
    int a[200];
    int b[200];
    main()
    {
    	int i,n;
    	scanf("%d",&n);
    	for(i=0;i<n;i++)
    	{
    		scanf("%d%d",&a[i],&b[i]);
    	}
    	int t=0;
    	int min=999999999;
    	for(i=0;i<n;i++)
    	{
    		if(min>a[i])
    		{
    			min=a[i];
    		}
    		t=t+min;
    		min=min+b[i];
    		
    	}
    	printf("%d",t);
    	
    }
    

    C++ :

    #include <iostream>
    using namespace std;
    int main(){
    	int n;
    	cin>>n;
    	int a[n],b[n];
    	for(int i=0;i<n;i++){
    		cin>>a[i]>>b[i];
    	}
    	int min=99999,t=0;
    	for(int i=0;i<n;i++){
    		if(min>a[i]){
    			min=a[i];
    		}
    		t=t+min;
    		min=min+b[i];
    	}
    	cout<<t;
    }
    
    • 1

    Information

    ID
    10600
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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