1 solutions
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0
C :
#include<stdio.h> int a[200]; int b[200]; main() { int i,n; scanf("%d",&n); for(i=0;i<n;i++) { scanf("%d%d",&a[i],&b[i]); } int t=0; int min=999999999; for(i=0;i<n;i++) { if(min>a[i]) { min=a[i]; } t=t+min; min=min+b[i]; } printf("%d",t); }
C++ :
#include <iostream> using namespace std; int main(){ int n; cin>>n; int a[n],b[n]; for(int i=0;i<n;i++){ cin>>a[i]>>b[i]; } int min=99999,t=0; for(int i=0;i<n;i++){ if(min>a[i]){ min=a[i]; } t=t+min; min=min+b[i]; } cout<<t; }
- 1
Information
- ID
- 10600
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By