1 solutions

  • 0
    @ 2025-3-3 16:33:39

    C :

    #include <stdio.h>
    void main()
    {
    	int n;
    	scanf("%d",&n);
    	if(n%2==0){
    		printf("%d\n",2);
    	}
    	if(n%3==0){
    		printf("%d\n",3);
    	}
    	if(n%5==0){
    		printf("%d\n",5);
    	}
    	if(n%7==0){
    		printf("%d\n",7);
    	}
    	  
    }
    

    C++ :

    #include <iostream>
    using namespace std;
     
    int main(){
    	int n;
    	cin>>n;
    	if(n % 2 == 0){
    		cout<<2<<endl;
    	}
    	
    	if(n % 3 == 0){
    		cout<<3<<endl;
    	}
    	
    	if(n % 5 == 0){
    		cout<<5<<endl;
    	}
    	
    	if(n % 7 == 0){
    		cout<<7<<endl;
    	}
    }
    
    

    Python :

    n = int(input())  
    if n % 2 == 0:
        print(2)
    if n % 3 == 0:
        print(3)
    if n % 5 == 0:
        print(5)
    if n % 7 == 0:
        print(7)
    
    
    • 1

    【入门】请问一个整数n能够被2、3、5、7中哪些数整除

    Information

    ID
    10608
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
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