1 solutions

  • 0
    @ 2025-3-3 16:33:39

    C :

    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
    	int n;
    	scanf("%d",&n);
    	if(n>90)
    		printf("yes\n");
    	return 0;
    }
    //Author: ITProgrammer
    

    C++ :

    #include <iostream>
    using namespace std;
    int main(){
       int a;
       cin>>a;
       if(a >= 90){
       	  cout<<"yes"<<endl;
       }
       return 0;
    }
    
    

    Python :

    num=int(input())
    if num >90:
        print('yes')
    
    • 1

    Information

    ID
    10610
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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