1 solutions
-
0
C :
#include <stdio.h> #include <stdlib.h> int main() { int n; scanf("%d",&n); if(n>90) printf("yes\n"); return 0; } //Author: ITProgrammer
C++ :
#include <iostream> using namespace std; int main(){ int a; cin>>a; if(a >= 90){ cout<<"yes"<<endl; } return 0; }
Python :
num=int(input()) if num >90: print('yes')
- 1
Information
- ID
- 10610
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By