1 solutions
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0
C :
#include<stdio.h> void main() { int n; double p; scanf("%d",&n); if(n>=30){ p=n; }else if(n>=20&&n<=29){ p=1.2*n; }else if(n>=10&&n<=19){ p=1.5*n; }else{ p=1.8*n; } printf("%.1f",p); }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int a; double b; cin>>a; if(a >= 30){ b = a * 1; }else if(a >= 20){ b = a *1.2; }else if(a >= 10){ b = a * 1.5; }else{ b = a * 1.8; } cout<<fixed<<setprecision(1)<<b<<endl; return 0; }
Python :
n=int(input()) if n>=30: s=n elif n>=20: s=n*1.2 elif n>=10: s=n*1.5 else: s=n*1.8 print('%.1f'%s)
- 1
Information
- ID
- 10613
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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