1 solutions

  • 0
    @ 2025-3-3 16:33:39

    C :

    #include<stdio.h>
    void main()
    {
    	int t,m,n;
    	scanf("%d%d",&m,&n);
    	t=(n-m)*30;
    	printf("%d\n",t);
    
      }  
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
    
    	int m,n;
    	cin>>m>>n;
    	cout<<(n-m)*30<<endl;
    	
    
    
    	return 0;
    }
    
    

    Python :

    m,n=map(int,input().split())
    if n-m!=0:
        s=(n-m)*30
    if n-m==0:
        s=360
    print(s)
    
    
    • 1

    Information

    ID
    10629
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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