1 solutions
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0
C :
#include <stdio.h> void main() { int m,n,a; scanf("%d%d",&m,&n); if(m>n){ a=(m-n)*m; }else{ a=(n-m)*n; } printf("%d",a); }
C++ :
#include<bits/stdc++.h> using namespace std; int main(){ int a,b; cin>>a>>b; if(a>b){ cout<<a*a-a*b<<endl; }else{ cout<<b*b-a*b<<endl; } }
Python :
x = input().split() m = int(x[0]) n = int(x[1]) if m > n: print((m - n) * m) if m < n: print((n - m) * n)
- 1
Information
- ID
- 10633
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By