1 solutions

  • 0
    @ 2025-3-3 16:33:39

    C :

    
    
    #include <stdio.h>
    void main()
    {
    	int m,n,a;
    	scanf("%d%d",&m,&n);
    	if(m>n){
    		a=(m-n)*m;
    	}else{
    		a=(n-m)*n;
    	}
    	printf("%d",a);
    }
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
        int a,b;
        cin>>a>>b;
        if(a>b){
        	cout<<a*a-a*b<<endl;
    	}else{
    		cout<<b*b-a*b<<endl;
    	}
        
    }
    

    Python :

    x = input().split()
    m = int(x[0])
    n = int(x[1])
    if m > n:
        print((m - n) * m)
    if m < n:
        print((n - m) * n)
    
    
    • 1

    Information

    ID
    10633
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By