1 solutions

  • 0
    @ 2025-3-3 16:33:39

    C :

    #include <stdio.h>
    void main()
    {
    	int a,b,h;
    	double s;
    	scanf("%d %d %d",&a,&b,&h);
    	s=(a+b)*h/2.0;
    	printf("%.1f\n",s);
     } 
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
    
    	float a,b,h;
    	cin>>a>>b>>h;
    	cout<<fixed<<setprecision(1)<<(a+b)*h/2<<endl;
    
    
    	return 0;
    }
    
    

    Python :

    a,b,h=map(int,input().split())
    s=(a+b)*h/2
    print('%.1f'% s)
    
    
    • 1

    Information

    ID
    10638
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By