1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; int main(){ double n,x,y; cin>>n>>x>>y; cout<<(int)((n * 1000 + y * 10) / (x * 10 + y * 10)); return 0; }
Python :
sr=input().split() n=float(sr[0])*100 k=float(sr[1]) j=float(sr[2]) m=n//(k+j) y=n%(k+j) if y>=k: print("%d"%(m+1)) else: print("%d"%m)
- 1
Information
- ID
- 10640
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By