1 solutions

  • 0
    @ 2025-3-3 16:33:40

    C :

    #include <stdio.h>
    void main()
    
    {
    	double i,r,s,p=3.14;
    	scanf("%lf",&i);
    	r=i/2.0/p;
    	s=3.14*r*r; 
    	printf("%.2f",s);
     }
    

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    
    int main(){
    	double s,c,r,pi = 3.14;
    	cin>>c;
    	r = c / (2 * pi);
    	s = pi * r * r;
    	cout<<fixed<<setprecision(2)<<s<<endl;
    	 
        return 0;
    }
    
    

    Python :

    # 接受输入周长
    x = float(input())
    # 圆周率3.14
    p = 3.14
    # 计算半径
    r = x / (2 * p)
    # 计算面积
    s = r * r * p
    print('%.2f' % s)
    
    
    • 1

    Information

    ID
    10646
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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