1 solutions
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0
C :
#include <stdio.h> void main() { double i,r,s,p=3.14; scanf("%lf",&i); r=i/2.0/p; s=3.14*r*r; printf("%.2f",s); }
C++ :
#include<bits/stdc++.h> using namespace std; int main(){ double s,c,r,pi = 3.14; cin>>c; r = c / (2 * pi); s = pi * r * r; cout<<fixed<<setprecision(2)<<s<<endl; return 0; }
Python :
# 接受输入周长 x = float(input()) # 圆周率3.14 p = 3.14 # 计算半径 r = x / (2 * p) # 计算面积 s = r * r * p print('%.2f' % s)
- 1
Information
- ID
- 10646
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By