1 solutions

  • 0
    @ 2025-3-3 16:33:40

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    //路径总数和路径
    int a[100][100],t=0;                 
     //四种移动规则
    int x[4]={2,1,-1,-2},y[4]={1,2,2,1};
    
    //输出结果 
    void print(int n)
    {
        t++;
        cout<<t<<":";
    	for(int i=1;i<n;i++){
    		cout<<a[i][1]<<","<<a[i][2]<<"->";	
    	}
    	
    	cout<<"4,8"<<endl;
    }
    
    //递归回溯 
    void search(int k)
    {
    	//往4个方向跳
    	for (int i=0;i<=3;i++){ 
    		//判断马不越界
    		if (a[k-1][1]+x[i]>=0&&a[k-1][1]+x[i]<=4 
    		     &&a[k-1][2]+y[i]>=0&&a[k-1][2]+y[i]<=8){
    		     	//保存当前马的位置
    				a[k][1]=a[k-1][1]+x[i];                              
    				a[k][2]=a[k-1][2]+y[i];
    				if (a[k][1]==4&&a[k][2]==8){
    					print(k);
    				}else{
    					search(k+1);//搜索下一步	
    				} 
    			 
    		}
    	} 
    }
    
    int main(){
    	a[1][1]=0;
    	a[1][2]=0;
    	//从坐标(0,0)开始往右跳第二步
    	search(2); 
    }
    
    
    • 1

    Information

    ID
    10671
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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