1 solutions

  • 0
    @ 2025-3-3 16:33:40

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
      int n,m;
      cin>>m>>n;
      int m1=m,n1=n,s1=m*n;                        //计算正方形的个数s1
      while (m1!=0&&n1!=0)
       {
          m1--;n1--;
          s1+=m1*n1;  
       }
      int s2=((m+1)*(n+1)*m*n)/4-s1;             // 计算长方形的个数s2
      cout<<s1<<" "<<s2<<endl; 
    }
    
    
    • 1

    Information

    ID
    10673
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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