1 solutions
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0
C :
#include<stdio.h> int main() { int a; scanf("%d",&a); int b=(a/1000+5)%10; int c=(a/100+5)%10; int d=(a/10+5)%10; int e=(a+5)%10; int h; printf("%d",h=e*1000+d*100+c*10+b); return 0; }
C++ :
#include<iostream> using namespace std; int main(){ int x,n,a,b,c,d; cin>>n; a=n/1000; b=n/100%10; c=n/10%10; d=n%10; a=(a+5)%10; b=(b+5)%10; c=(c+5)%10; d=(d+5)%10; x=d*1000+c*100+b*10+a*1; cout<<x<<endl; }
Python :
n=int(input()) a=(n//1000+5)%10 b=(n//100%10+5)%10 c=(n//10%10+5)%10 d=(n%1000+5)%10 S=d*1000+c*100+b*10+a print(S)
- 1
Information
- ID
- 10714
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By