1 solutions
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0
C :
#include<stdio.h> main() { int i,n,b=0,c=0; scanf("%d",&n); int a[n]; for(i=0;i<n;i++) { scanf("%d",&a[i]); } for(i=0;i<n;i++) { if(a[i]%2!=0) { b+=a[i]; } else c+=a[i]; } printf("%d\n%d",b,c); }
C++ :
#include <iostream> using namespace std; int main(){ int i,n,j=0,o=0; int a[5000]; cin>>n; for(i=0;i<n;i++){ cin>>a[i]; if(a[i]%2!=0){ j=j+a[i]; }else{ o=o+a[i]; } } cout<<j<<endl; cout<<o<<endl; }
Python :
n=int(input()) l1=[] for i in range(1,n+1): a=int(input()) l1.append(a) a=0 b=0 for i in range(0,n): if l1[i]%2==0: a+=l1[i] else: b+=l1[i] print(b,a)
- 1
Information
- ID
- 10766
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By