1 solutions
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0
C :
#include<stdio.h> int main(){ int n,i,sum=1; scanf("%d",&n); for(i = 1;i <= n;i++){ sum *= i; //等同于 sum = sum * i; } printf("%d",sum); return 0; }
C++ :
#include <iostream> using namespace std; int main(){ int i,s = 1,n; cin>>n; for(i = 1;i <= n;i++){ s = s * i; } cout<<s<<endl; return 0; }
Python :
n = int(input()) i = 1; s = 1 while i <= n: s = s * i i += 1; print(s)
- 1
Information
- ID
- 10815
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By