1 solutions

  • 0
    @ 2025-3-3 16:33:58

    C :

    #include<stdio.h> 
    int main()
    {
        double n,i,s=0;
        scanf("%lf",&n); 
        for(i=1; i<=n ;i++)
        {
                 s= s+1/i;
        }
        printf("%.3lf\n",s);
        return 0;
    }
    

    C++ :

    #include <iostream>
    #include <iomanip>
    using namespace std;
    
    int main(){
    	int i,n;
    	double s = 0;
    	cin>>n;
    	
    	for(i = 1;i <= n;i++){
    		s = s + 1.0 / i;
    	} 
    	cout<<fixed<<setprecision(3)<<s<<endl;
    	
    }
    
    

    Python :

    n =  int(input());
    s = 0;
    for i in range(1,n + 1):
        s = s + 1/i;
    print('%.3f' % s);
    
    
    
    
    • 1

    Information

    ID
    10816
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By