1 solutions
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0
C :
#include<stdio.h> int main() { double n,i,s=0; scanf("%lf",&n); for(i=1; i<=n ;i++) { s= s+1/i; } printf("%.3lf\n",s); return 0; }
C++ :
#include <iostream> #include <iomanip> using namespace std; int main(){ int i,n; double s = 0; cin>>n; for(i = 1;i <= n;i++){ s = s + 1.0 / i; } cout<<fixed<<setprecision(3)<<s<<endl; }
Python :
n = int(input()); s = 0; for i in range(1,n + 1): s = s + 1/i; print('%.3f' % s);
- 1
Information
- ID
- 10816
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By