1 solutions
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0
C :
#include<stdio.h> int main(){ int n,i,sum=0; scanf("%d",&n); for(i = 1;i <= n;i++){ sum += i * i; } printf("%d",sum); return 0; }
C++ :
#include<iostream> using namespace std; int main(){ int n,s,i; s=0; i=0; cin>>n; while(n>=1&&n<=200){ s=n*n; i=i+s; n=n-1; } cout<<i<<endl; }
Python :
n=int(input()) i=1 s=0 while i<=n: s=s+i*i i+=1 print(s)
- 1
Information
- ID
- 10818
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By