1 solutions

  • 0
    @ 2025-3-3 16:33:59

    C :

    #include<stdio.h>
    #include<stdlib.h>
    int main()
    {	float n,s;
    	scanf("%f",&s);
    	if(s<=15)
    	{	
    		n=s/1.5;
    		printf("%.2f",n);
    	}
    	if(s>15)
    	{
    		n=(s-15)/2.5+10;
    	printf("%.2f",n);
    	}
    }
    	
    

    C++ :

    #include<iostream>
    #include <iomanip> 
    using namespace std;
    int main(){
    	double m,n;
    	cin>>m;
    	if(m<=15){
    		n=m/1.5; 
    	}else{
    		n=(m-15)/2.5+10;
    	}
    	cout<<fixed<<setprecision(2)<<n; 
    	return 0;
    }
    

    Python :

    n=int(input())
    if n<=15:
        print('%.2f' %(n/1.5))
    else :
        print('%.2f' %(10+(n-15)/2.5))
    
    
    
    • 1

    Information

    ID
    10828
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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