1 solutions
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0
C :
#include<stdio.h> #include<stdlib.h> int main() { float n,s; scanf("%f",&s); if(s<=15) { n=s/1.5; printf("%.2f",n); } if(s>15) { n=(s-15)/2.5+10; printf("%.2f",n); } }
C++ :
#include<iostream> #include <iomanip> using namespace std; int main(){ double m,n; cin>>m; if(m<=15){ n=m/1.5; }else{ n=(m-15)/2.5+10; } cout<<fixed<<setprecision(2)<<n; return 0; }
Python :
n=int(input()) if n<=15: print('%.2f' %(n/1.5)) else : print('%.2f' %(10+(n-15)/2.5))
- 1
Information
- ID
- 10828
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By