1 solutions

  • 0
    @ 2025-3-3 16:33:59

    C :

    #include<stdio.h> 
    
    int main(){ 
    	int i,j,n,a[101],k,temp;
    	
    	scanf("%d",&n) ;
    	
    	for(i = 0;i < n;i++){
    		scanf("%d",&a[i]); 
    	} 
    	
    
    	for(i = 0;i < n-1;i++) {
    		k = i; 
    		for(j = i + 1;j < n;j++){
    			if(a[j] < a[k]){   
    				k = j;
    			}
    
    		} 
    		
    		if(k != i){
    			temp = a[i];
    			a[i]  = a[k];
    			a[k] = temp;
    		}
    	
    	
    	} 
    	
    	for(i = 0;i < n;i++){
    		printf("%d ",a[i]);
    	}
    	return 0; 	  
    } 
    

    C++ :

    #include <iostream>
    using namespace std;
    
    int main(){
    	//选择排序 
    	int n,i,j,min,t;
    	cin>>n;
    	int a[n];
    	for(i = 0;i < n;i++){
    		cin>>a[i];
    	}
    	
    	for(i = 0;i < n - 1;i++){
    		min = i;
    		for(j = i;j < n;j++){
    			if(a[j] < a[min]){
    				min = j;
    			}
    		}
    		
    		if(min != i){
    			t = a[min];
    			a[min] = a[i];
    			a[i] = t;
    		}
    	}
    	
    	for(i = 0;i < n;i++){
    		cout<<a[i]<<" ";
    	}
    }
    

    Python :

    #!/usr/bin/env python3
         
    n = int(input())
    list1 = []
    list1 = input().split()
    list2 = []
    for i in range(0,n,1):
    	m = int(list1[i])
    	list2.append(m)
    else:
        list2.sort(reverse=False)
        for i in list2:
            print(i,end=" ")	 
    
    • 1

    Information

    ID
    10858
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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