1 solutions

  • 0
    @ 2025-3-3 16:33:59

    C :

    #include<stdio.h>
    int main()
    {
    	int a;
    	scanf("%d",&a);
    	int b=a/100%10;
    	int c=a/10%10;
    	int d=a/1%10;
    	printf("%d\n",d*100+c*10+b+a);
    		
    	return 0;
    }
    

    C++ :

    #include <iostream>
    #include <iomanip>
    using namespace std;
    
    int main(){
        int n;
        cin>>n;
        cout<<n+n/100+n/10%10*10+n%10*100<<endl;
    }
    

    Python :

    r = int(input())
    a = r // 100;
    b = r // 10 % 10
    c = r % 10;
    print(c * 100 + b * 10 + a + r)
    
    • 1

    Information

    ID
    10860
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By