1 solutions

  • 0
    @ 2025-3-3 16:33:59

    C :

    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
    	int a[6];
    	scanf("%d%d%d",&a[0],&a[1],&a[2]);
    	if(a[2]-a[1]==a[1]-a[0])
    	{
    		int i;
    		for(i=3;i<6;i++)
    			a[i]=a[i-1]+a[2]-a[1];
    	}
    	else if(a[2]/a[1]==a[1]/a[0])
    	{
    		int i;
    		for(i=3;i<6;i++)
    			a[i]=a[i-1]*(a[2]/a[1]);
    	}
    	printf("%d %d %d\n",a[3],a[4],a[5]);
    	return 0;
    }
    //Author: ITProgrammer
    

    C++ :

    #include<iostream>
    using namespace std;
    int main(){ 
       int a,b,c;
       cin>>a>>b>>c;
       if(c - b == b - a){ 
          int t = c - b;
          cout<<c + t <<" " <<c + 2 * t <<" " << c + 3 * t<<endl;
       }else{ 
          int t = c / b;
          cout<<c * t <<" " <<c * t * t <<" " << c * t * t * t<<endl;
       }
       return 0;
    }
    
    

    Python :

    a,b,c=map(int,input().split())
    if c-b==b-a:
        t=c-b
        print(c+t,c+t+t,c+t+t+t)
    else:
        t=c//b
        print(c*t,c*t*t,c*t*t*t)
    
    
    • 1

    Information

    ID
    10861
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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