1 solutions
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0
C :
#include<stdio.h> int main(){ double f,c1; int c; scanf("%d",&c); c1=(double)c; double k=9.0/5.0; f=k*c+32; printf("%.2f",f); return 0; }
C++ :
#include<iostream> #include<iomanip> using namespace std; int main(){ int c; cin>>c; double f=9.0/5*c+32; cout<<setiosflags(ios::fixed)<<setprecision(2)<<f<<endl; }
Python :
c=int(input()) f=9/5*c+32 print('%.2f'% f)
- 1
Information
- ID
- 10867
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By