1 solutions
-
0
C :
#include <stdio.h> int main(){ int a; scanf("%d",&a); float q; if(a <= 10){ q = 2.5; }else{ q = 2.5 + (a-10) * 1.5; } printf("%.2f",q); return 0; }
C++ :
#include<iostream> #include<iomanip> using namespace std; int main(){ double x,i; cin>>i; if(i<=10){ x=2.5; }else if(i>10){ x=2.5+(i-10)*1.5; } cout<<fixed<<setprecision(2)<<x<<endl; }
Python :
x = int( input() ) if x <= 10: y = 2.5 else: y = 2.5 +(x - 10) * 1.5 print('%.2f' % y)
- 1
Information
- ID
- 10890
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By