1 条题解
- 
  0
C :
#include<stdio.h> #include<math.h> double dayu(double a,double b,double c) { double m1=(-b+sqrt(b*b-4*a*c))/(a*2); double m2=(-b-sqrt(b*b-4*a*c))/(a*2); printf("x1=%.3lf x2=%.3lf",m1,m2); } double dengyu(double a,double b,double c) { double m1=(-b)/(2*a); printf("x1=x2=%.3lf",m1); } double xiaoyu(double a,double b,double c) { double m1=(-b)/(2*a); double t=sqrt(4*a*c-b*b)/(2*a); printf("x1=%.3lf+%.3lfi x2=%.3lf-%.3lfi",m1,t,m1,t); } int main() { int i,j; double a,b,c; scanf("%lf%lf%lf",&a,&b,&c); if(pow(b,2)-4*a*c>0) dayu(a,b,c); else if(pow(b,2)-4*a*c==0) dengyu(a,b,c); else xiaoyu(a,b,c); }C++ :
#include<iostream> #include<cmath> #include<cstdio> using namespace std; double disc,x1,x2,p,q; void big(int a,int b) //>0 { x1=(-b+sqrt(disc))/(2.0*a); x2=(-b-sqrt(disc))/(2.0*a); } void small(int a,int b) //<0 { p=-1.0*b/(2*a); q=sqrt(-disc)/(2*a); } void equal(int a,int b) //==0 { x1=x2=-1.0*b/(2*a); } int main() { int a,b,c; cin>>a>>b>>c; disc=b*b-4*a*c; if (disc>0) { big(a,b); printf("x1=%.3lf x2=%.3lf\n",x1,x2); } else if (disc==0) { equal(a,b); printf("x1=x2=%.3lf\n",x1); } else { small(a,b); printf("x1=%.3lf+%.3lfi x2=%.3lf-%.3lfi\n",p,q,p,q); } return 0; } 
- 1
 
信息
- ID
 - 2204
 - 时间
 - 1000ms
 - 内存
 - 128MiB
 - 难度
 - (无)
 - 标签
 - 递交数
 - 0
 - 已通过
 - 0
 - 上传者